(z^2+5)*(z^2-3z+4)=0

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Solution for (z^2+5)*(z^2-3z+4)=0 equation:


Simplifying
(z2 + 5)(z2 + -3z + 4) = 0

Reorder the terms:
(5 + z2)(z2 + -3z + 4) = 0

Reorder the terms:
(5 + z2)(4 + -3z + z2) = 0

Multiply (5 + z2) * (4 + -3z + z2)
(5(4 + -3z + z2) + z2(4 + -3z + z2)) = 0
((4 * 5 + -3z * 5 + z2 * 5) + z2(4 + -3z + z2)) = 0
((20 + -15z + 5z2) + z2(4 + -3z + z2)) = 0
(20 + -15z + 5z2 + (4 * z2 + -3z * z2 + z2 * z2)) = 0
(20 + -15z + 5z2 + (4z2 + -3z3 + z4)) = 0

Combine like terms: 5z2 + 4z2 = 9z2
(20 + -15z + 9z2 + -3z3 + z4) = 0

Solving
20 + -15z + 9z2 + -3z3 + z4 = 0

Solving for variable 'z'.

The solution to this equation could not be determined.

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